Page 1 of 1
III AUM Time left 0:28:27 (18 points) 0.01 mol of solid NaOH was added to a 500 mL solution containing 0.55 M CH=CH2COOH
Posted: Fri Apr 29, 2022 12:42 pm
by answerhappygod
- Iii Aum Time Left 0 28 27 18 Points 0 01 Mol Of Solid Naoh Was Added To A 500 Ml Solution Containing 0 55 M Ch Ch2cooh 1 (25.67 KiB) Viewed 28 times
III AUM Time left 0:28:27 (18 points) 0.01 mol of solid NaOH was added to a 500 mL solution containing 0.55 M CH=CH2COOH and 0.75 MC6H5CH2COONa (Ka for C6H5CH COOH = 4.9 x 10-6). Drag and drop the appropriate choices from below to fill the following table and answer the questions. Reaction Table OH(aq) (aq) (aq) + H2O() - Initial