150 g of methane (CH4) is combusted in NTP-conditions. How many liters of oxygen is needed? Unbalanced chemical equation

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answerhappygod
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150 g of methane (CH4) is combusted in NTP-conditions. How many liters of oxygen is needed? Unbalanced chemical equation

Post by answerhappygod »

150 g of methane (CH4) is combusted in NTP-conditions. How many
liters of oxygen is needed? Unbalanced chemical equation of this
reaction is CH4 + O2 -> CO2 + H2O.
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