We will use a Factor of Safety of 2.5. We will assume that there are 24 beams running across the short side of townhouse

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We will use a Factor of Safety of 2.5. We will assume that there are 24 beams running across the short side of townhouse

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We Will Use A Factor Of Safety Of 2 5 We Will Assume That There Are 24 Beams Running Across The Short Side Of Townhouse 1
We Will Use A Factor Of Safety Of 2 5 We Will Assume That There Are 24 Beams Running Across The Short Side Of Townhouse 1 (101.12 KiB) Viewed 27 times
We will use a Factor of Safety of 2.5. We will assume that there are 24 beams running across the short side of townhouse Total Load is 6600 pounds X 2.5 = 16500 LBS Spread across 24 beams = 16500 LBS/24 = 687.5 LBS The beam will be 20 feet long and the distributed load will be 687.5 Lbs/20 Feet = 35.00 Lbs/Ft Wo = 35.00 LBS/Ft FAY FBY! Use 1000 PSI as the Max Normal Stress for the wood beam omax = 1000 psi 1 Create a shear force/bending moment diagram 2 Identify the max bending moment
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