Consider the following elastic collision: (b) A second block of mass m2​=0.610 kg moving with velocity v2​=−1.71^m/s co

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answerhappygod
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Consider the following elastic collision: (b) A second block of mass m2​=0.610 kg moving with velocity v2​=−1.71^m/s co

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Consider The Following Elastic Collision B A Second Block Of Mass M2 0 610 Kg Moving With Velocity V2 1 71 M S Co 1
Consider The Following Elastic Collision B A Second Block Of Mass M2 0 610 Kg Moving With Velocity V2 1 71 M S Co 1 (87.22 KiB) Viewed 35 times
Consider the following elastic collision: (b) A second block of mass m2​=0.610 kg moving with velocity v2​=−1.71^m/s collides with the first block. Calculate the velocity of the centre of mass of the two-block system. vcm​=1.281 m/s^ Your last answer was interpreted as follows: 1.281
v2i∗​=−2.991 Your last answer was interpreted as follows: −2. (d) What are the final velocities of the blocks in the lab frame? v1f​=4.272 Your last answer was interpreted as follows: 4.2 v2f​=−1.908 Your last answer was interpreted as follows: −1 (e) Suppose the collision was inelastic. What is the change in ene
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