If 1 mol of solid is vaporized 12Na broken bonds are formed. Therefore L (Latent heat of sublimation) = 12 Na*E/2(E is t

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answerhappygod
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If 1 mol of solid is vaporized 12Na broken bonds are formed. Therefore L (Latent heat of sublimation) = 12 Na*E/2(E is t

Post by answerhappygod »

a) 0.50*L/Na (J/surface atoms)
b) 0.75*L/Na (J/surface atoms)
c) 0.25*L/Na (J/surface atoms)
d) 1.25*L/Na (J/surface atoms)
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