a) ip = 0.6cos(500t + π/4 + 88.5⁰)
b) ip = 0.6cos(500t + π/4 + 89.5⁰)
c) ip = 0.7cos(500t + π/4 + 89.5⁰)
d) ip = 0.7cos(500t + π/4 + 88.5⁰)
In the circuit shown below, the switch is closed at t = 0. Applied voltage is v (t) = 400cos (500t + π/4). Resistance R
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answerhappygod
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In the circuit shown below, the switch is closed at t = 0. Applied voltage is v (t) = 400cos (500t + π/4). Resistance R
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