a) The contribution of the image itself becomes more dominant
b) The contribution of the highpass filtered version of image becomes less dominant
c) All of the mentioned
d) None of the mentioned
High boost filtered image is expressed as: fhb = A f(x, y) – flp(x, y), where f(x, y) the input image, A is a constant a
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answerhappygod
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High boost filtered image is expressed as: fhb = A f(x, y) – flp(x, y), where f(x, y) the input image, A is a constant a
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