a) 6.02b + 16.81 + \(20log_{10}\frac{R}{σ_x}\)
b) 6.02b + 16.81 – \(20log_{10} \frac{R}{σ_x}\)
c) 6.02b – 16.81 – \(20log_{10} \frac{R}{σ_x}\)
d) 6.02b – 16.81 – \(20log_{10} \frac{R}{σ_x}\)
By combining \(\Delta=\frac{R}{2^{b+1}}\) with \(P_n=\sigma_e^2=\Delta^2/12\) and substituting the result into SQNR = 10
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
By combining \(\Delta=\frac{R}{2^{b+1}}\) with \(P_n=\sigma_e^2=\Delta^2/12\) and substituting the result into SQNR = 10
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!