a) \(\frac{-1}{2\sqrt x}×tan(\sqrt x+\sqrt y)\)
b) \(\frac{-1}{2\sqrt x}×cos(\sqrt x+\sqrt y)\)
c) \(\frac{-1}{2\sqrt x}×sin(\sqrt x+\sqrt y)\)
d) \(\frac{-1}{\sqrt x}×sin(\sqrt x+\sqrt y)\)
Find \(\frac{\partial u}{\partial x}\) where \(u=cos(\sqrt x+\sqrt y)\).
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
Find \(\frac{\partial u}{\partial x}\) where \(u=cos(\sqrt x+\sqrt y)\).
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!