a) 1⁄12 et – 1⁄13 Cos(-t) – 1⁄12 Sin(-t) – 1⁄156 e-5t
b) 1⁄12 e-t – 1⁄13 Cos(t) – 1⁄12 Sin(t) – 1⁄156 e5t
c) 1⁄12 et – 1⁄13 Cos(t) – 1⁄12 Sin(t) – 1⁄156 e-5t
d) 1⁄12 et + 1⁄13 Cos(t) + 1⁄12 Sin(t) + 1⁄156 e-5t
Find the inverse laplace transform of \(\frac{1}{(s^2+1)(s – 1)(s + 5)}\).
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answerhappygod
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Find the inverse laplace transform of \(\frac{1}{(s^2+1)(s – 1)(s + 5)}\).
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