a) \(\frac{1}{2\sqrt{2}} tan^{-1}(\frac{4x+2y+1}{\sqrt{2}})=x+c \)
b) \(\frac{1}{\sqrt{2}} cot^{-1}(4x+2y+1)=x+c \)
c) \(\frac{1}{\sqrt{2}} tan^{-1}(\frac{4x+2y+1}{\sqrt{2}})=c \)
d) cot-1(4x+2y+1)=x+c
Solution of the differential equation \(\frac{dy}{dx} = (4x+2y+1)^2\) is ______
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answerhappygod
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Solution of the differential equation \(\frac{dy}{dx} = (4x+2y+1)^2\) is ______
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