a) sec-1 (x) – 1⁄2 ln(1 + x2)
b) xtan-1 (x) – 1⁄2 ln(1 + x2)
c) xsec-1 (x) – 1⁄2 ln(1 + x2)
d) tan-1 (x) – 1⁄2 ln(1 + x2)
Find the value of ∫tan-1(x)dx.
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Find the value of ∫tan-1(x)dx.
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