a) x=40, y=40, z=40
b) x=38, y=50, z=32
c) x=50, y=40, z=30
d) x=80, y=30, z=50
Divide 120 into three parts so that the sum of their products taken two at a time is maximum. If x, y, z are two parts,
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answerhappygod
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Divide 120 into three parts so that the sum of their products taken two at a time is maximum. If x, y, z are two parts,
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