a) 1
b) 1⁄2
c) 1⁄7
d) 2⁄7
view answer
Given that limit exists find \(lt_{(x,y,z)\rightarrow(-1,-1,-1)}\frac{tan((x-1)(y-2)(z-3))}{(x-1)(y-6)(z+7)}\)
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Given that limit exists find \(lt_{(x,y,z)\rightarrow(-1,-1,-1)}\frac{tan((x-1)(y-2)(z-3))}{(x-1)(y-6)(z+7)}\)
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