a) 1
b) 3⁄5
c) 1⁄2
d) 0
view answer
Given that limit exists find \(lt_{(x,y,z)\rightarrow(-2,-2,-2)}\frac{sin((x+2)(y+5)(z+1))}{(x+2)(y+7)}\)
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Given that limit exists find \(lt_{(x,y,z)\rightarrow(-2,-2,-2)}\frac{sin((x+2)(y+5)(z+1))}{(x+2)(y+7)}\)
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