Find the error in the Decryption pseudo code for RC5 – for i = 1 to r do RDi-1 = ((RDi – S [2xi+1] >>> LDi ) ⊕ L

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answerhappygod
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Find the error in the Decryption pseudo code for RC5 – for i = 1 to r do RDi-1 = ((RDi – S [2xi+1] >>> LDi ) ⊕ L

Post by answerhappygod »

a) B= RD0 + S [1];
b) for i = 1 to r do
c) LDi-1 = ((LDi – S [2xi] >>> RDi-1) ⊕ RDi-1);
d) A = LD0 – S [0];
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