a) d_i is the ith bit of a byte ‘d’ whose hex value is 0x15
b) d_i is the ith bit of a byte ‘d’ whose hex value is 0x05
c) d_i is the ith bit of a byte ‘d’ whose hex value is 0x25
d) d_i is the ith bit of a byte ‘d’ whose hex value is 0x51
The inverse s-box permutation follows, b’_i = b_(i+2) XOR b(i+5) XOR b_(i+7) XOR d_i Here d_i is
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The inverse s-box permutation follows, b’_i = b_(i+2) XOR b(i+5) XOR b_(i+7) XOR d_i Here d_i is
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