a) 2nπ + π/6 < θ < 2nπ + 5π/6
b) 2nπ + π/3 < θ < 2nπ + 5π/3
c) 2nπ + π/6 ≤ θ ≤ 2nπ + 5π/6
d) 2nπ + π/3 ≤ θ ≤ 2nπ + 5π/3
For what value of θ, 1 lies between the roots of the quadratic equation 3x2 – 3sinθ x – 2cos2θ = 0?
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
For what value of θ, 1 lies between the roots of the quadratic equation 3x2 – 3sinθ x – 2cos2θ = 0?
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!