a) p=2
b) p=1
c) p=-1
d) p=-2
Find the value of p such that the lines \(\frac{x-1}{3}=\frac{y+4}{p}=\frac{z-9}{1}\) \(\frac{x+2}{1}=\frac{y-3}{1}=\fr
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answerhappygod
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Find the value of p such that the lines \(\frac{x-1}{3}=\frac{y+4}{p}=\frac{z-9}{1}\) \(\frac{x+2}{1}=\frac{y-3}{1}=\fr
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