a) \(\frac{x+1}{-1}=\frac{y+8}{-8}=\frac{z-5}{5}\)
b) \(\frac{x+1}{7}=\frac{y+8}{-3}=\frac{z-5}{-3}\)
c) \(\frac{x-7}{7}=\frac{y+8}{-3}=\frac{z-3}{-3}\)
d) \(\frac{x+1}{7}=\frac{y+8}{-8}=\frac{z+5}{3}\)
Find the cartesian equation of the line which is passing through the point (-1, -8, 5) and parallel to the vector \(7\ha
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answerhappygod
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Find the cartesian equation of the line which is passing through the point (-1, -8, 5) and parallel to the vector \(7\ha
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