a) \(\frac{7x^4}{4}-2e^{2x}+\frac{2}{x}+C\)
b) \(\frac{7x^4}{4}+2e^{2x}+\frac{2}{x}+C\)
c) \(\frac{7x^4}{4}-2e^{2x} \frac{2}{x^2}+C\)
d) \(\frac{7x^4}{8}+2e^{2x}-\frac{4}{x}+C\)
Find \(\int \,7x^8-4e^{2x}-\frac{2}{x^2} \,dx\).
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answerhappygod
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Find \(\int \,7x^8-4e^{2x}-\frac{2}{x^2} \,dx\).
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