a) (\(\frac{1}{\sqrt{12}}\),-1) and (\(\frac{1}{\sqrt{12}}\),-1)
b) (-\(\frac{1}{\sqrt{12}}\),3) and (-\(\frac{1}{\sqrt{12}}\),-1)
c) (\(\frac{1}{\sqrt{12}}\),2) and (-\(\frac{1}{\sqrt{12}}\),-2)
d) (\(\frac{1}{\sqrt{12}}\),3) and (\(\frac{1}{\sqrt{12}}\),-2)
Find the point at which the tangent to the curve y=\(\sqrt{4x^2+1}\)-2 has its slope2.
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
Find the point at which the tangent to the curve y=\(\sqrt{4x^2+1}\)-2 has its slope2.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!