a) \(\frac{9}{91}\)
b) \(\frac{27}{273}\)
c) \(\frac{-27}{273}\)
d) \(\frac{-9}{91}\)
Solve: \(\frac{3x+7}{12} + \frac{22x-1}{3}\) = 1.
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answerhappygod
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Solve: \(\frac{3x+7}{12} + \frac{22x-1}{3}\) = 1.
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