ty′−2y=t5sin(2t)−t3+4t4

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answerhappygod
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ty′−2y=t5sin(2t)−t3+4t4

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Ty 2y T5sin 2t T3 4t4 1
Ty 2y T5sin 2t T3 4t4 1 (4.29 KiB) Viewed 28 times
ty′−2y=t5sin(2t)−t3+4t4
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