I need some help with these 2 homework questions. Is it also possible to break it down for me to understand clearly?

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answerhappygod
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I need some help with these 2 homework questions. Is it also possible to break it down for me to understand clearly?

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I need some help with these 2 homework questions. Is it alsopossible to break it down for me to understand clearly?
I Need Some Help With These 2 Homework Questions Is It Also Possible To Break It Down For Me To Understand Clearly 1
I Need Some Help With These 2 Homework Questions Is It Also Possible To Break It Down For Me To Understand Clearly 1 (232.24 KiB) Viewed 78 times
I Need Some Help With These 2 Homework Questions Is It Also Possible To Break It Down For Me To Understand Clearly 2
I Need Some Help With These 2 Homework Questions Is It Also Possible To Break It Down For Me To Understand Clearly 2 (189.29 KiB) Viewed 78 times
(1 point) Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. Suppose you have an LFSR with 6 state bits. The first 12 bits of output produced by this LFSR are 100011011101 = S0 S1 S2 S3 S4 S5 S6 S7 S8 S9 S10 $11. The first bit produced is the leftmost bit and the bit most recently produced is the rightmost bit. a) What is the initial state of the LFSR? Please enter your answer as unspaced binary digits (e.g. 010101 to represent S5 = 0, $4 = 1, S3 = 0, $₂ = 1, S₁ = 0, so = 1). b) What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 010101 to represent P5 = 0, P4 = 1, P3 = 0, P2 = 1, P₁ = 0, Po = 1).
(1 point) Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = 4. The plaintext given by 00011000 =X0X1 X2 X3 X4 X5 X6 X7 when encrypted by the LFSR produced the ciphertext 01110000 = Уо У1 Уг Уз Уз У5 У6 У7 · What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent P3 = 0, P2 = 1, P₁ = 0, po = 1).
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