in the next cell Ag / AgCl (sat) Cl-(1.0 mol L-1) // Fe2+ (0.05 mol L-1), Fe3+ (0.19 mol L-1) / Pt The potential in V of

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answerhappygod
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in the next cell Ag / AgCl (sat) Cl-(1.0 mol L-1) // Fe2+ (0.05 mol L-1), Fe3+ (0.19 mol L-1) / Pt The potential in V of

Post by answerhappygod »

in the next cell
Ag / AgCl (sat) Cl-(1.0 mol L-1) // Fe2+ (0.05 molL-1), Fe3+ (0.19 mol L-1) / Pt
The potential in V of the indicator electrode would be:
EºFe+3/Fe+2= 0.771 V.
Select one:a. -0.805Vb. 0.805Vc.1.004Vd. 0.606V
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