1. (Table: TV and Aggressiveness) In a fictional study, a pretest–posttest design was used to examine the influence of a

[answerhappygod]

1. (Table: TV and Aggressiveness) In a fictional study, apretest–posttest design was used to examine the influence of atelevision program on children's aggressiveness. The number ofaggressive responses was measured during an observation period bothbefore and after the television program. Fill out the rough outlineof hypothesis testing below using the data in the table todetermine if the number of aggressive behaviors differs after thechildren view the television program. Assume this is a two-tailedhypothesis test.
Steps of Hypothesis Testing:
QUESTION 1
TV and Aggressiveness: Step 1 of Hypothesis Testing Answers(hint: make sure you read the whole answer, every piece must becorrect)
A.) Population 1: All children in the United States.
Population 2: All children not in the United States.
3 Assumptions met?
Normal Dist- We don't know, but samples size is less than 30people, so we need to be cautious about generalization
Random Selection - We don't know, but likely a conveniencesample, so it would not be random selection
DV Scale- No- whether or not they watched TV is not a number
Comparison distribution, type of test, and mean? Distribution ofmean differences, single samples t-test, mean = 0
B.) Population 1:All children who have not seen the TVprogram.
Population 2: All children who have seen the TV program.
3 Assumptions met?
Normal Dist- We don't know, but samples size is less than 30people, so we need to be cautious about generalization
Random Selection - We don't know, but likely a conveniencesample, so it would not be random selection
DV Scale- Yes- # of aggressive responses
Comparison distribution and mean? Distribution of means, singlesample t-test, mean = 0
B.) Population 1: All children who have not seen the TVprogram.
Population 2: All children who have seen the TV program.
3 Assumptions met?
Normal Dist- We don't know, but samples size is less than 30people, so we need to be cautious about generalization
Random Selection - We don't know, but likely a conveniencesample, so it would not be random selection
DV Scale- Yes- # of aggressive responses
Comparison distribution, type of test, and mean? Distribution ofmean differences, paired samples t-test, mean = 0
QUESTION 2
TV and Aggressiveness Step 2 Hypothesis Testing
A.) Null hypothesis: The average number of aggressive behaviorsbefore watching the TV program is bigger than after having watchedthe TV program. (H0: u1 > u2)
Research Hypothesis: The average number of aggressive behaviorsbefore watching the TV program is smaller than after having watchedthe TV program (H1: u1< u2)
B.) Null hypothesis:The average number of aggressive behaviorsbefore watching the TV program is the same as after having watchedthe TV program. (H0: u1 = u2)
Research Hypothesis: The average number of aggressive behaviorsbefore watching the TV program is different than after havingwatched the TV program. (H1: u1 /= u2)
C.) Null hypothesis: The average number of aggressive behaviorsbefore watching the TV program is different than after havingwatched the TV program. (H0: u1/= u2)
Research Hypothesis: The average number of aggressive behaviorsbefore watching the TV program is the same as after having watchedthe TV program (H1: u1 = u2)
D. )Null hypothesis:The average number of aggressive behaviorsbefore watching the TV program is smaller than after having watchedthe TV program (H0: u1< u2)
Research Hypothesis: The average number of aggressive behaviorsbefore watching the TV program is bigger than after having watchedthe TV program. (H1: u1 > u2)
QUESTION 3
TV and Aggressiveness Step 3 Hypothesis Testing (hint: these maybe rounded slighlty different than yours, that's okay! Your answershould still be extremely close to one listed.)
A.) µM = µ = 0
Mdifference: 1.71
SS = 43.43
s = 2.69
sM = 1.015
B.) µM = µ = 1
Mdifference: 12.02
SS = 6.43
s = 1.83
sM = 0.489
C.) µM = µ = 0
Mdifference: 10.25
SS = 6.43
s = 1.13
sM = 1.243
D,) µM = µ = 0
Mdifference: 12.46
SS = 41.23
s =2.69
sM = 1.015
QUESTION 4
TV and Aggressiveness Step 4 Hypothesis Testing
A.) df:13
Critical Values: +/- 2.161
B.) df: 7
Critical Values: +/- 2.365
C.) df: 6
Critical Values: 2.447
QUESTION 5
TV and Aggressiveness Step 5 Hypothesis Testing (not necessarilyin APA)
A.) t = 1.68
B.) t = -41.02
C.) t = 1.017
D.) t = 2.447
QUESTION 6
TV and Aggressiveness Step 6 Hypothesis Testing- in APA format(READ CAREFULLY)
A.) t(7) = 1.68, p > .05 We fail to reject the nullhypothesis because our t score does not fall in the criticalrange.
B.) t(6) = 1.68, p > .05; We fail to reject thenull hypothesis because our t score does not fall in the criticalrange.
C.) t(6) = 1.68, p < .05; We reject the nullhypothesis because our t score falls in the critical range.
D.) t(7) = 1.68, p < .05; We reject the nullhypothesis because our t score falls in the criticalrange.