Revenue. Suppose the graph of the revenue R(x) and cost C(x) are shown below where R(x) and -x²–2x+2 x= C(x) = x² + 2 6.
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Revenue. Suppose the graph of the revenue R(x) and cost C(x) are shown below where R(x) and -x²–2x+2 x= C(x) = x² + 2 6.
Revenue. Suppose the graph of the revenue R(x) and cost C(x) are shown below where R(x) and -x²–2x+2 x= C(x) = x² + 2 6.75 -10.6667 L -2 The profit, or the area enclosed between the two curves is 10.6667 R(X) -6.75 Note: Round to 4 digits after the decimal point, if rounding is required none of the other answers -0.3333 O -1 0.3333 y 1 C(x) 1 2 X ☹
Derivative. The derivative of h(x) is e 3 + e h'(x) Oh'(x) Oh'(x) = + 5) Oh'(x)= (4x + (3 5)(8x) + e(4x²+ -5) 2 e¯³(-3)(3 + e(4x² + 5)_e(4x² + 5)(8x)(e¯³) (3 + e(4x² + 5)₂2 -e (4x² + 5)(8x)(e-³) (3 + e(4x²+ + 5)₂2 none of the other answers e¯³(−3)(3 + e(4x² + 5)). (3 + e (4x² + (4x² + -5)) 5)(8x)(e-³)
Differentiable Function. If a differentiable function f(x) satisfies f(-2) = f(2) then there exists a c in (-2, 2) with O f(c) = 0 O f"(c) < 0 O f"(c) = 0 f'(c) < 0 O f'(c) > 0 O f'(c) = 0 O f (c) > O Of "(c) > 0
Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. In(a) - In(b) = In(a - b) for all positive real numbers a and b. 4 True. Take a = 4 and b = 2. Then In(a) - In(b) = In(4) - In(2) In = In(2). And In(a - b) = In(4-2) = In(2). True. This is one of the Laws of Logarithms. False. In(a - b) = In(a) - In(b) only for negative real numbers a and b. False. In(a - b) = In(a) - In(b) only for positive real numbers a > b. False. Take a = 2 and b = 1. Then In(a) - In(b) = In(2) In(1) In(2) - 0= In(2). But In(a - b) = In(2 - 1) = n(1) = 0.