Hi below is code for a "simple illumination model". Similar to phong or gouraud shading. My question is do I multiply the final "i" variable ( 3.45 in this example) times each RGB component?
thanks
I*R
I*G
I*B
Hi Below Is Code For A Simple Illumination Model Similar To Phong Or Gouraud Shading My Question Is Do I Multiply Th 1 (719.94 KiB) Viewed 43 times
Example 5-1 Simple Illumination Model Recalling Fig. 5-5 assume that at point P on the surface the normal, light, and sight vectors are n = L = S = By inspection the reflection vector R is then R = i +2j+k Assuming that there is only one object in the scene, d = 0 and K = 1. The light source is assumed to be 10 times more intense than the ambient light; i.e., la = 1 and = 10. The surface is to have a shiny metallic appearance. Hence, most of the light will be specularly reflected. Thus, assume k, = 0.8, kdka= 0.15 and n = 5. Note that k, + kd= 0.95, which implies that 5% of the energy from the light source is absorbed. Determining the various elements of the illumination model yields or j i + 2j- k i + 1.5j + 0.5k n. Î= n-L j.(-i+2j-k) √(-1)² + (2)² + (−1)² nL 0 = cos ¹ (2/6)= 35.26° 2 V6
and or Finally then and R.S R-S= RS Here (i+2j+k) (i+1.5j +0.5k) √(1)²+(2)² + (1)²(1)² + (1.5)² + (0.5) 1 = (1)(0.15) + (10/1)[(0.15)(2/6) + (0.8)(4.5/√/21)] = 0.15 + 10(0.12 +0.73) = 8.65 Because the sight vector is almost coincident with the reflection vector, an at the point P. However, if the position observer would see a bright highlig of the observer is changed such that the sight vector is S=i+1.5j-0.5k 4.5 4.5 V6√3.5 V21 a = cos¹ (4.5/√21) = 10.89° R-S= R-S RS 11 a = 40.2° 3.5 V21 /= 0.15 +10(0.12 +0.21) 3.45 Gianntly reduced.
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