Som Given 80 Vca Dine To Neutsal 277 V Van 277 Lo Von 277 2 120 Vcn 277 2 290 C Von Von Van Von Vcn 1 (31.72 KiB) Viewed 34 times
why is or how is tan inverse 239.88/-415.5=30 deg
same as
180-30=150 deg????????
since point is in second quadrant
Som Given 80 Vca Dine To Neutsal 277 V Van 277 Lo Von 277 2 120 Vcn 277 2 290 C Von Von Van Von Vcn 2 (31.72 KiB) Viewed 34 times
Som Given :- 80, VCA dine to Neutsal = 277 V VAN = 277 Lo Von 277 2-120' VCN = 277 2-290 . C VON = - VON VAN VON = [ VCN = VAN = 277 2-240 = - - -238.5+ 239.88 i = VCN 277 20 -415.5+ 239.88 i 480L tan¹ (23 -120° = 277 Cos (-290') + 277 i sin (-290) 277 (os (0) +120° 480 L150 Aus Ve-VN 239.88 -915-5 V] VA - VN 277 Van 277 Sin (0)i
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