Assume that K > 0 for the system shown in Figure 1. R(s) + K(s +20) s(s+ 2)(s + 3) Figure 1: Feedback system of Question

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Assume That K 0 For The System Shown In Figure 1 R S K S 20 S S 2 S 3 Figure 1 Feedback System Of Question 1 (45.63 KiB) Viewed 30 times

Assume That K 0 For The System Shown In Figure 1 R S K S 20 S S 2 S 3 Figure 1 Feedback System Of Question 2 (47.59 KiB) Viewed 30 times

Assume that K > 0 for the system shown in Figure 1. R(s) + K(s +20) s(s+ 2)(s + 3) Figure 1: Feedback system of Question 1 C(s) (a) (5 points) Find the range of K that will make the system stable. (b) (5 points) Determine the number of poles on the left-half-plane, the right-half-plane and on the jw-axis for K = 2
Information sheet The Routh table for a polynomial of the form as + a₂s³ + a₂s² + a₂ + a $³ 80 b₁ = 1 1+ Kp 1 K₂ C₁₂ e(∞o) ramp e (co) parabola d₁ = = 1 Ka a4 0+5 a3 Position constant, K₂ = limG (s) 194 laz 5+0 Velocity constant, K, =lim sG(s) az 193 a₂ lb₁ b₂ b₂ 9₂₁₂ Acceleration constant, K₁ = lim s²G(s) System error e(00) step a₂ 0-5 b₂ = d₂ = The final value theorem for a negative unity feedback system e (co) = lim sE (s) = lim sR(s) [1+G(S)] = ! lim Static error constants a₂ 194 laz |a3 |b₁ az b₂ dol 0 -18 C₂ =0 = 0 SR(s) $+01+G(S) b₂ = C3 = d₂ = do 0 a₁ 0 az 0 az az |b₁ 0 b₂ -1 ol C₁ 0 = 0 = 0