In the circuit of Figure, the equivalent capacitance is 5.0 μF 8.0 μF 3.5 μF O 27.31 μF O 33.75 μF 11.43 uF O10.17 F O 1

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answerhappygod
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In the circuit of Figure, the equivalent capacitance is 5.0 μF 8.0 μF 3.5 μF O 27.31 μF O 33.75 μF 11.43 uF O10.17 F O 1

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In the circuit of Figure, the equivalent capacitance is 5.0 μF 8.0 μF 3.5 μF O 27.31 μF O 33.75 μF 11.43 uF O10.17 F O 17.21 µF 1.5 μF +0.75 μF 15 μF
A proton (m = 1.6726 x 10-27 kg and q = 1.6 x 10-19 C) with speed 1.5 x 105m/s falls through a potential difference of -10 volts. What is the speed reached? O 2.04 x 105 m/s O 1.56 x 105 m/s- O 2.04 x 104 m/s O 8.80 x 105 m/s O 4.37 x 104 m/s
The figure shows two connected wires that are made of the same material. The current entering the wire on the left is 2.0 A and in that wire the electron drift speed is vd What is the electron drift speed in the wire on the right side? 1.0 mm O 2vd O4vd Ovd Ovd/4 Ovd/2 2.0 mm -
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