Lab 6 Inheritance and Polymorphism For this problem, we will implement inheritance and polymorphism The architecture is

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: Lab 6 Inheritance And Polymorphism For This Problem We Will Implement Inheritance And Polymorphism The Architecture Is 1 (30.06 KiB) Viewed 29 times

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Lab 6 Inheritance and Polymorphism For this problem, we will implement inheritance and polymorphism The architecture is shown as the following figure. We have a base class Role, and three derived classes Role Warrior Archer Magician • Class Role Role(string ID, int level, int money, int hp) Public constructor - ID: Role's name. - level: Role's level - money: Amount of money that the role has - hp: Role's hp. void PrintAllinfo() Print this character's name, level, money and hp. You can see the format in the sample output virtual void ShowRole) Pure virtual function. String geti Public function to get the Role's ID. (name) • Class Warrior - Warrior (string ID, int level, int money, int hp) Public constructor. This class inhents the class Role void ShowRole) Print "Role's name is Warrior • Class Archer Archer (string ID, int level, int money, int hp) Public constructor. This class inherits the class Role. void ShowRole 0 Print Role's name is Archer

. Class Magician Magician(string ID, int level, int money, int hp) Public constructor. This class inherits the class Role. · void ShowRole) Print "Role's name is Magician" Class Staff Private: Bool isMagician(Role role) Check whether the dynamic casting is performed successfully Public: Staff(string staffName, int damage) staffName: The name of the staff damage: The damage that the staff do Bool equipable(Role role); Check whether the role can equip this staff. Function bool is Magician(Role role) In this function, we would like to assign a pointer of a base class type (Role) to a pointer of its derived class type (Magician). The advantage of dynamic casting is that it can be used to check whether casting is performed successfully Implement dynamic casting, and return true and print "Player is a magician # casting success. Return False and print out "bad cast" if casting failed. Using this function to check whether the player is a magician bool equipable(Role role) In this function, you need to use the isMagician to check whether the player is magician, if the player is magician then he/she can equip the staff. Example: Roleplayer 1 - Warrior("Steve", 1, 1987,200): Staff staff Staff("Flame",10); Staff->equiable(player): cout << endl; playeri - Magician("Lisa", 15,981, 145); Staff->equiable(player2); cout << endl; Output will be :

bad cast. Lisa is a magician Lisa can equip this staft Hint: 1. We will provide templates (main.cpp. Warrior.cpp. Warrior.h, and staff.h). 2. Please declare the class in the header file respectively. Input Format The number in the first line is the number of test cases Then, each following line contains "10, level, money, HP about that character Output Format Print who can equip the staff class -- Magician), and their character information Sample Input & Output INPUT: Steve, Warrior, 1, 1987,200 Legolas, Archer, 99, 99999, 6000 Lisa, Magician, 15.981, 145 Rose, Magician, 30, 234, 668 4 OUTPUT ID is : Steve Level is: 1 Money is : 1987 Hp is : 200 Role Steve is Warrior ID is: Legolas Level is : 99 Money is : 99999 Hp is : 6000 Role Legolas is Warrior ID is : Lisa Level is: 15 Money is : 981 Hp is : 145

4 0 4 Role Lisa is Magician ID is : Rose Level is: 30 Money is : 234 Hp is: 668 Role Rose is Magician Checking whether the role can equip a staff error bad_cast error bad_cast Lisa can equip staff_flame. Rose can equip staff_flame.