Help!!
A use of rows is to obtain an approximate value for a convergent) row 2 a, by calculating a final sum ar i = no i = no One difficulty with this method is knowing how large n must be to obtain sufficient accuracy. This is often given as how many current digits, or how many decimal places we need. A practical way to do this is to see which decimals do not change if we increase n (a lot), for example it doubles. The method is not safe, and can potentially give completely wrong answers, but in practice it almost always works. Practitioners (engineers and physicists) like this method, while mathematicians are often a little more skeptical. In this thesis I will suppress my skepticism and ask you to use this method to find the sum of the row 25/+3 with 4 decimal places accuracy. 2-201+2 1 This should be done by starting with the upper limit n = 2 = 2 then double the number of joints repeatedly until the difference between the last two estimates less than 10 = 0.001. What is the smallest number k so that the difference -3 is less than 10 2k+1 251+3 og Σ = 2 -20/+2 25i + 3 -23-201+2 ? Some hints: One way to calculate a sum is by def sumn0,n) summen - 0 for iin range(no, n+1): summen - summen +ali) return summen all) is a function expression for the i-th clause, and must of course be adjusted according to the thesis text: It is best if you manage to automate the search with a while loop that stops when the difference is small enough, but a partially manual variant also works (but you have to count on some repetitions)
Help!!
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