We wrap a light, nonstretching cable around a solid cylinder of mass 5.0 kg and diameter of 0.120 m, which rotates with

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We wrap a light, nonstretching cable around a solid cylinder of mass 5.0 kg and diameter of 0.120 m, which rotates with

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We Wrap A Light Nonstretching Cable Around A Solid Cylinder Of Mass 5 0 Kg And Diameter Of 0 120 M Which Rotates With 1
We Wrap A Light Nonstretching Cable Around A Solid Cylinder Of Mass 5 0 Kg And Diameter Of 0 120 M Which Rotates With 1 (29.24 KiB) Viewed 9 times
We wrap a light, nonstretching cable around a solid cylinder of mass 5.0 kg and diameter of 0.120 m, which rotates with frictionless bearings, as shown in the Figure. We pull the free end of the cable with a constant 9.0 N force. What is the cable's acceleration? (a) 9,0 N 50 kg 0.120 m (b) Facts tangent to the cylinder's surface, so its lever arm is the radius R. F=9.0 N Y R=0.060m Mg n. The weight and normal force both act on a line through the axis of rotation, so they exert no torque. -X G Counterclockwise torques are positive.
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