A mass of 0.1 kilograms is attached to a spring whose spring constant is 1.6 Newtons per meter. With the mass at its equ

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A mass of 0.1 kilograms is attached to a spring whose spring constant is 1.6 Newtons per meter. With the mass at its equ

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A Mass Of 0 1 Kilograms Is Attached To A Spring Whose Spring Constant Is 1 6 Newtons Per Meter With The Mass At Its Equ 1
A Mass Of 0 1 Kilograms Is Attached To A Spring Whose Spring Constant Is 1 6 Newtons Per Meter With The Mass At Its Equ 1 (31.5 KiB) Viewed 10 times
A mass of 0.1 kilograms is attached to a spring whose spring constant is 1.6 Newtons per meter. With the mass at its equilibrium position, its support begins to oscillate, which imparts a force on the mass according to the formula, F(t) = 2.5 sin(8t). Assuming that there is no damping on the system, it can be modeled using the differential equation, 0.1y"(t) + 1.6y(t) = 2.5 sin(8t). Write a set of initial conditions to model the particular circumstance, then use that to find the equation of motion for the mass.
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