questions (15 to 19). * The maximum order of the polynomial that we get from the data is:
Given 1 f(x) = x* – 23 – –sin (1x) defined over the interval [0, 6] where h=1. Use N.G.F. 3 - I sin Starting from (x=3), d3P3(x)/dx3 at x=3 using central derivative is:
Given 1 f(x) = x+ – 23 – – sin (TX) defined over the interval [0, 6] where h=1. Use N.G.F. - I a Starting from (x=1), dP4(x)/dx at X=1 is:
Given 1 sin (1) TT defined over the interval [0, 6] where h=1. Use N.G.F. f (x) = x4 – 23 = – – Starting from x=3; d2P3(x)/dx? at x=3 is: 68 None 88 102
Given f (x) = x4 – x3y – I sin (13) defined over the interval [0, 6] where h=1. Use N.G.F. Starting from x=2; The absolute error (dP2(x)/dx - df(x)/dx| at x=3 is: 17 14 10 None
T Given 1 f(x) = x4 – 23 - sin (73) defined over the interval [0, 6] where h=1. Use N.G.F. Interpolation to solve T Given 1 f(x) = x4 – 23 - sin (73) defined over the interval [0, 6] where h=1. Use N.G.F. Interpolation to solve questi
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