1 (60 pts) 5,000 kg/hr of coal enter a combustion chamber. The coal contains (by mass) 75% C, 17% H, 2% S, and 6% noncom

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answerhappygod
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1 (60 pts) 5,000 kg/hr of coal enter a combustion chamber. The coal contains (by mass) 75% C, 17% H, 2% S, and 6% noncom

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1 60 Pts 5 000 Kg Hr Of Coal Enter A Combustion Chamber The Coal Contains By Mass 75 C 17 H 2 S And 6 Noncom 1
1 60 Pts 5 000 Kg Hr Of Coal Enter A Combustion Chamber The Coal Contains By Mass 75 C 17 H 2 S And 6 Noncom 1 (62.34 KiB) Viewed 11 times
1 (60 pts) 5,000 kg/hr of coal enter a combustion chamber. The coal contains (by mass) 75% C, 17% H, 2% S, and 6% noncombustible ash. The coal burns with excess air that comes at a rate of 3,000 kmole/hr (see picture below). All of the ash and 6% (by mass) of the carbon in the coal leave the bottom of the combustion chamber as a molten slag. The remaining 94% of carbon burns to CO and CO₂. All hydrogen in the coal becomes water vapor and all S burns to SO₂. Gas chromatography indicates that the mole fractions of CO₂ and CO in the flue gas are at a ratio of 10/1. Use the appendix for atomic weights. (a) Calculate the % excess air in the flue gas. (b) (c) (d) (e) Calculate the mass flowrate of the molten slag. Calculate molar flowrates ₁, ₂, 3, 4, and n (see picture below). Calculate the flue gas composition (by mole) on a dry basis. Calculate the flue gas composition (by mole) on a wet basis. 5000 kg coal / h 0.75 kg C/ kg 0.17 kg H/kg 0.02 kg S/kg 0.06 kg ash / kg 3000 kmol air / h 0.21 kmol O₂/kmol 0.79 kmol N/kmol C+Q₂-CQ₂ 2H + 1/2 Q₂ -->H₂O S+ O₂SO₂ C + 1/2 Q→→ CO n, (kmol Q₂/h) n₂ (kmol N₂/h) n (kmol CO₂/h) 0.1 n, (kmol CO /h) n₂ (kmol SQ, / h) n (kmol H₂O / h) mo kg slag/h
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