Tutorial 1 Curves 20 3085m 3 5 A A Horizontal Grade Meets A 3 5 Grade At 3035 Meter Chainage And 218 905m Elevation 1 (56.79 KiB) Viewed 13 times
explain in detail
Tutorial 1 Curves 20 3085m -3.5% a. A horizontal grade meets a -3.5% grade at 3035 meter chainage and 218.905m elevation. A vertical curve of 26 meter length with 4 meter peg intervals is to be introduced. Calculate the necessary elevations on the curve. b. A parabolic vertical curve is to be set out connecting two uniform grader of chainage and
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!