(3) The position of the 2 kg object's center of mass is r = 6i + 4j + 2k (m) and its velocity is v = -16i +8j – 12k (m/s

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3 The Position Of The 2 Kg Object S Center Of Mass Is R 6i 4j 2k M And Its Velocity Is V 16i 8j 12k M S 1 (59.66 KiB) Viewed 42 times

(3) The position of the 2 kg object's center of mass is r = 6i + 4j + 2k (m) and its velocity is v = -16i +8j – 12k (m/s). The external forces act on the object is given by ΣF = 2t i + 4j. r (a) What is the object's angular momentum Ho about the origin O at t₂ =1 sec? (b) Determine the angular impulse exerted on the object during interval of time from t₁ =0 to t2 =4s.