m- An object attached to a spring undergoes simple harmonic motion modeled by the differential equation d² x + kx = 0 wh

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M An Object Attached To A Spring Undergoes Simple Harmonic Motion Modeled By The Differential Equation D X Kx 0 Wh 1 (58 KiB) Viewed 29 times

m- An object attached to a spring undergoes simple harmonic motion modeled by the differential equation d² x + kx = 0 where x(t) is the displacement of the mass (relative to equilibrium) at time t, m is the dt² mass of the object, and k is the spring constant. A mass of 6 kilograms stretches the spring 0.75 meters. = Use this information to find the spring constant. (Use g k The previous mass is detached from the spring and a mass of 5 kilograms is attached. This mass is displaced 0.5 meters above equilibrium (above is positive and below is negative) and then launched with an initial velocity of 0.5 meters/second. Write the equation of motion in the form x(t) = c₁ cos(wt) + c₂ sin(wt). Do not leave unknown constants in your equation. x(t): = 9.8 meters/second²) Rewrite the equation of motion in the form x (t) = A cos (Bt - 6). Do not leave unknown constants in ㅠ ㅠ your equation. Leave as an angle between and 2 2 x(t): =