I have two integrands that are equal, but written differently. When using Partial Fraction Decomposition, I get two diff

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I Have Two Integrands That Are Equal But Written Differently When Using Partial Fraction Decomposition I Get Two Diff 1 (47.09 KiB) Viewed 96 times

I have two integrands that are equal, but written differently. When using Partial Fraction Decomposition, I get two different values for A. Why is this happening when the integrands are equal? See my work attached. 630 (1-x)(1+x) Use Parfal Fractions A+B (1-x)(1+x) (*) (1+x) 1= A[+] + 8[1-*] x = 1: X=-1: 1= 2A +O A=V2 1= 0428 B÷12 These two are (x-1)(x+1) Use ا۔ Portial Fractions AB (x41) -1 = A[X] +B[X=1] x=1-1= 2A +0 = -1/2 (X-1)(x+1) (x-1) X= -1:-1 = -28 13 = 12 Why do I get different valves for A?