Question 15 1 pts 7T Given f (0) = 24 – 2013 sin (12) defined over the interval [0, 6] where h=1. Use N.G.F. Interpolati

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Question 15 1 pts 7T Given f (0) = 24 – 2013 sin (12) defined over the interval [0, 6] where h=1. Use N.G.F. Interpolati

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Question 15 1 Pts 7t Given F 0 24 2013 Sin 12 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolati 1
Question 15 1 Pts 7t Given F 0 24 2013 Sin 12 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolati 1 (14.6 KiB) Viewed 76 times
Question 15 1 Pts 7t Given F 0 24 2013 Sin 12 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolati 2
Question 15 1 Pts 7t Given F 0 24 2013 Sin 12 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolati 2 (7.39 KiB) Viewed 76 times
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Question 15 1 pts 7T Given f (0) = 24 – 2013 sin (12) defined over the interval [0, 6] where h=1. Use N.G.F. Interpolation to solve questions (15 to 19). * The maximum order of the polynomial that we get from the data is:

Question 16 1 pts Starting from (x=3), d3P3(x)/dx? at x=3 using central derivative is:
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