- Question 15 1 Pts 7t Given F X 24 2013 Sin 12 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolatio 1 (14.61 KiB) Viewed 63 times
- Question 15 1 Pts 7t Given F X 24 2013 Sin 12 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolatio 2 (7.2 KiB) Viewed 63 times
- Question 15 1 Pts 7t Given F X 24 2013 Sin 12 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolatio 3 (4.37 KiB) Viewed 63 times
- Question 15 1 Pts 7t Given F X 24 2013 Sin 12 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolatio 4 (9.05 KiB) Viewed 63 times
- Question 15 1 Pts 7t Given F X 24 2013 Sin 12 Defined Over The Interval 0 6 Where H 1 Use N G F Interpolatio 5 (7.82 KiB) Viewed 63 times
Question 15 1 pts 7T Given f (x) = 24 – 2013 sin (12) defined over the interval [0,6] where h=1. Use N.G.F. Interpolation to solve questions (15 to 19). * The maximum order of the polynomial that we get from the data is:
Question 17 2 pts dP4(x)/dx at x=0 is:
Question 18 2 pts Starting from x=2; The absolute error (dP2(x)/dx - df(x)/dx| at x=4 is: None 25 27 23
Question 19 1 pts Starting from x=3; d2P3(x)/dxat x=3 is: None 88 68 102