The solution of (1 + y2)dx = (tan- y - x)dy is (a) (W) = tan-' - 1+ ce-tan- (b) x(y) = tan-?y + ce-tan-ly (c) x(y) = tan

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answerhappygod
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The solution of (1 + y2)dx = (tan- y - x)dy is (a) (W) = tan-' - 1+ ce-tan- (b) x(y) = tan-?y + ce-tan-ly (c) x(y) = tan

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The Solution Of 1 Y2 Dx Tan Y X Dy Is A W Tan 1 Ce Tan B X Y Tan Y Ce Tan Ly C X Y Tan 1
The Solution Of 1 Y2 Dx Tan Y X Dy Is A W Tan 1 Ce Tan B X Y Tan Y Ce Tan Ly C X Y Tan 1 (19.99 KiB) Viewed 76 times
The solution of (1 + y2)dx = (tan- y - x)dy is (a) (W) = tan-' - 1+ ce-tan- (b) x(y) = tan-?y + ce-tan-ly (c) x(y) = tan-ly-1+ ceta (d) y(x) = tan-20-1+cetan-, (e) y(x) = tan-+x+ce tan d (a) (b) O (c) 0 (d) (e)
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