Suppose that X has a discrete uniform distribution on the integers 0 through 9. Determine the mean, variance, and standa

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Suppose that X has a discrete uniform distribution on the integers 0 through 9. Determine the mean, variance, and standa

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Suppose that X has a discrete uniform
distribution on the integers 0 through 9. Determine the mean,
variance, and standard deviation of the random
variable Y = 5X and compare to the
corresponding results for X.
The random variable X has a binomial
distribution with n =
10 and p = 0.01. Determine the following
probabilities.
Suppose that f(x)
= e−x for 0
< x. Determine the following:
An e-mail message will arrive at a time uniformly distributed
between 9:00 A.M. and 11:00 A.M. You check e-mail at 9:15 A.M. and
every 30 minutes afterward.
Please answer this using MATLAB and Screenshot it. Thank you
Suppose That X Has A Discrete Uniform Distribution On The Integers 0 Through 9 Determine The Mean Variance And Standa 1
Suppose That X Has A Discrete Uniform Distribution On The Integers 0 Through 9 Determine The Mean Variance And Standa 1 (36.99 KiB) Viewed 440 times
Please answer this using MATLAB and Screenshot it. Thank
you!!.
SS WP 3.4.3 Suppose that X has a discrete uniform distribution on the integers o through 9. Determine the mean, variance, and standard deviation of the random variable Y = 5X and compare to the corresponding results for X. V Answer E(X) = 4.5 E(Y) = 22.5 Oy = 14.36 Solution The range of Y is 0, 5, 10, ..., 45, E(X) = (0 +9)/2 = 4.5 E(Y) = = 0(1/10) + 5(1/10) + ... + 45(1/10) 5[0(0.1) +1(0.1) +...+9(0.1)] = 5E(X) 5(4.5) 22.5 8.25, V(Y) = 5(8.25) = 206.25, ay = 14.36 = V(X) =

The random variable X has a binomial distribution with n = 10 and p = 0.01. Determine the following probabilities. WP SS 3-5-3 a. P(X = 5) V Answer 2.40 x 10-8 V Solution P(X = 5) = (19)0.0 0.01%(0.99)" = = 2.40 x 10-8 b. P( X2) Answer 0.9999 Solution P(X<2) = (69)0.01°0.99) + (11)0.01*(0.999+ (19)0.01%0.998 + 0.9999 c. P(X29) Answer 9.91 x 10-18 Solution P(X > 9) = (19)0.01°(0.99)*+ (19)0.01"(0.99)0 = 9.91 x 10-18 d. P(3 < X<5) Answer 1.138 x 10-4 Solution P(3< X<5) = = (19)0.01°(0.997 + ()0.01$(0.99) = 1.138 x 10-4

4.3.1 WP SS VS suppose that f(x) = 1.5x2 for –1<x< 1. Determine the mean and variance of X. Answer E(X) = 0, V(X) = 0.6 Solution E(X) = -1 (1.5x’dx = 1.531., = 0 4 1.52°(2 - 0)?da = 1.5 j 1.5 L = 0.6 V(X) = xada -1 =

1-4-7 An e-mail message will arrive at a time uniformly distributed between 9:00 A.M. and 11:00 A.M. You check e-mail at 9:15 A.M. and every 30 minutes afterward. a. What is the standard deviation of arrival time (in minutes)? Answer Ox = 34.64 b. What is the probability that the message arrives less than 10 minutes before you view it? Answer 1/3 c. What is the probability that the message arrives more than 15 minutes before you view it? Answer 1/2
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