A study performed a memorization task under two conditions: (1) with irrelevant background speech and (2) in silence. Th

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A study performed a memorization task under two conditions: (1) with irrelevant background speech and (2) in silence. Th

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A Study Performed A Memorization Task Under Two Conditions 1 With Irrelevant Background Speech And 2 In Silence Th 1
A Study Performed A Memorization Task Under Two Conditions 1 With Irrelevant Background Speech And 2 In Silence Th 1 (67.89 KiB) Viewed 86 times
A Study Performed A Memorization Task Under Two Conditions 1 With Irrelevant Background Speech And 2 In Silence Th 2
A Study Performed A Memorization Task Under Two Conditions 1 With Irrelevant Background Speech And 2 In Silence Th 2 (107.35 KiB) Viewed 86 times
A study performed a memorization task under two conditions: (1) with irrelevant background speech and (2) in silence. The difference in the error rates for the two conditions—called the relative difference in error rate (RDER)—was computed for each subject. Descriptive statistics for the RDER values are reproduced in the following printout. Conduct a test to determine if the average difference in error rates for all subjects who perform the memorization tasks exceeds 75 percent. Use a= 0.01 and interpret the results practically. N 70 Mean 78.193107 Analysis Variable: RDER Std Dev Minimum 63.2514201 – 19.2670444 Maximum 253.3698128
ZE (Round to two decimal places as needed.) Find the observed significance level (p-value) of the test. p-value = (Round to three decimal places as needed.) Use a = 0.01 to conduct the test and then interpret the results in the words of the problem. оооо O A. Fail to reject the null hypothesis that the average difference in error rates exceeds 75 percent because the p-value is greater than the level of significance a = 0.01. B. Reject the null hypothesis that the average difference in error rates exceeds 75 percent because the p-value is greater than the level of significance a = 0.01. C. Fail to reject the null hypothesis that the average difference in error rates exceeds 75 percent because the p-value is less than the level of significance a = 0.01. OD. Reject the null hypothesis that the average difference in error rates exceeds 75 percent because the p-value is less than the level of significance a =0.01.
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