- Dhruv Rameshbhai Savani Problem 5 9 Perpendicular Polarized Plane Wave Propagate In Glass And Incident At An Angle 0 Up 1 (59.28 KiB) Viewed 61 times
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Dhruv Rameshbhai Savani Problem 5-9 Perpendicular polarized plane wave propagate in glass and incident at an angle 0; upon a planar boundary with air. It considers that the glass and air is lossless and glass relative dielectric constant is &ir = 3,0 and air relative dielectric constant is €2. = 1. It is known that the wavelength in glass is n = 5 cm. The magnitude of the electric field phasor in air at x=0 and z=0 is Ě (0,0) = 10 Vim Calculate: 1) Magnitude of reflection coefficient when incident angle is 0; = 0, = 70°; 2) Magnitude of the eletric field phasor in air at x = 0 and at distance zo = 5 cm from boundary Ěj (0,30) if the angle of incidence is 0; = 0 a.; 3) Magnitude of the electric field phasor in air at x = 0 and at distance zo = 5 cm from boundary \}(0,30) if the angle of incidence is 0; = 06 = 15°. all