3. Given the initial partial pressures of (Prais) = 0.0500 atm, (Pria) = 0.180 atm, and (PC) = 0.250 atm at 250°C for th
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3. Given the initial partial pressures of (Prais) = 0.0500 atm, (Pria) = 0.180 atm, and (PC) = 0.250 atm at 250°C for th
3. Given the initial partial pressures of (Prais) = 0.0500 atm, (Pria) = 0.180 atm, and (PC) = 0.250 atm at 250°C for the following reaction, what must each equilibrium partial pressure be? PC1s (g) → PC1s (g) + Cla (g) K₂=2.15
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