The enthalpy of reaction is -11.7 kJ/mol for the following reaction: HCN(aq) + NaOH(aq) --> H2O(l) + NaCN(aq) If 0.689g

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answerhappygod
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The enthalpy of reaction is -11.7 kJ/mol for the following reaction: HCN(aq) + NaOH(aq) --> H2O(l) + NaCN(aq) If 0.689g

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The enthalpy of reaction is -11.7 kJ/mol for the following
reaction: HCN(aq) + NaOH(aq) --> H2O(l) + NaCN(aq) If 0.689g of
HCN react with excess NaOH in a coffee cup calorimeter, what amount
will the temperature change by? Use 63.4 g as the total mass in the
calorimeter and use 4.184 J/gC as the specific heat. Give your
answer to 2 decimal places.
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